Something about Poker odds..

[LuckyNumberD]

Hey,

there's something about poker odds I'm not fully understanding.
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Let's say you have a Flushdraw on the Flop. and in a 0.05/0.10 stakes game the pot stands 40c.

your opponent bets 10.c so...

9 outs = 36%
10+40=50 = 1:5 = 6 => 100:6= 16%

so this call is good (right ?? )
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so now on the turn our opponent bets again, and no flush yet.

This time he bets 60c. in a 60c. pot. so..

9 outs = 18%
60+60= 120 = 1:2 = 3 =>100:3= 33%

So this is a bad call now...
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Up to this point everything's right. but here's my question:

On the flop you count the odds of seeing two cards for the price of 10c. but in fact you only got to see One card... the second cost you 60c.

So you can only use the rule of 4 in an all-in or something ??

This is something i really don't get. I hope someone can help me with this

thanks !!

[The Professor]

There is alot of depth which you could go into with the poker maths, and the section in the course really sets out the basics and gets it incorporated into your game.

You are correct in the calculation on the flop is the calculation of the chances that you will hit your card with two cards to come - this is assuming that you get to see both the turn and the river.

So you are correct in that this is 100% accurate only with an all in because otherwise the calculation doesn't take into account what bet you would have to call on the turn if you need to see the second card. But it also doesn't take into account the extra money you would win if you hit your flush on the turn.

This whole aspect drifts into the realms of Implied pot odds which is a much more subjective subject and is touched upon towards the end of the course.

So you are not wrong in what you say, but the whole idea is getting you thinking about what chance you have to hit your hand and that you don't get involved in chasing cards that in the long run won't make you a profit.